diff --git a/tex-stuff/math.tex b/tex-stuff/math.tex
index b575d75..2d2c1f7 100644
--- a/tex-stuff/math.tex
+++ b/tex-stuff/math.tex
@@ -77,14 +77,21 @@ the price $p_{b_a}$ bidder $a$ is willing to pay. $\forall j: p_j < p_{j+1}$.
 
 \subsubsection{Round 1: Encrypt bid}
 
+The message has $k$ parts, each consisting of $10$ Points plus an additional $3$
+Points for the last proof. Therefore the message is $10k*32 + 3*32 = 320k + 96$
+bytes large.
+
 \begin{enumerate}
-	\item Set $b_{aj}=\begin{cases}g & \mathrm{if}\quad j=b_a\\0 & \mathrm{else}\end{cases}$ and publish $\alpha_{aj}=b_{aj}+r_{aj}y$ and $\beta_{aj}=r_{aj}g$ for each j.
-	\item Prove that $\forall j:(\alpha_{aj}, \beta_{aj})$ decrypts to either $0$ or $g$.
-	\item Prove that $\forall j: ECDL_y\left(\left(\sum_{j=1}^k\alpha_{aj}\right) - g\right) = ECDL_g\left(\sum_{j=1}^k\beta_{aj}\right)$
+	\item $\forall j:$ Set $b_{aj}=\begin{cases}g & \mathrm{if}\quad j=b_a\\0 & \mathrm{else}\end{cases}$ and publish $\alpha_{aj}=b_{aj}+r_{aj}y$ and $\beta_{aj}=r_{aj}g$ for each j.
+	\item $\forall j:$ Prove that $(\alpha_{aj}, \beta_{aj})$ decrypts to either $0$ or $g$.
+	\item Prove that $ ECDL_y\left(\left(\sum_{j=1}^k\alpha_{aj}\right) - g\right) = ECDL_g\left(\sum_{j=1}^k\beta_{aj}\right)$
 \end{enumerate}
 
 \subsubsection{Round 2: Compute outcome}
 
+The message has $nk$ parts, each consisting of $5$ Points. Therefore the message
+is $5nk*32 = 160nk$ bytes large.
+
 \begin{enumerate}
 	\item Compute and publish for each $i$ and $j$: \\[2.0ex]
 		$\gamma_{ij}^{\times a} = m_{ij}^{+a}\displaystyle\left(\left(\sum_{h=1}^n\sum_{d=j+1}^k\alpha_{hd}\right)+\left(\sum_{d=1}^{j-1}\alpha_{id}\right)+\left(\sum_{h=1}^{i-1}\alpha_{hj}\right)\right)$ and \\[2.0ex]